(x+1)^2/3=27

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Solution for (x+1)^2/3=27 equation: 


x in (-oo:+oo)

((x+1)^2)/3 = 27 // - 27

((x+1)^2)/3-27 = 0

((x+1)^2)/3+(-27*3)/3 = 0

(x+1)^2-27*3 = 0

x^2+2*x-80 = 0

x^2+2*x-80 = 0

x^2+2*x-80 = 0

DELTA = 2^2-(-80*1*4)

DELTA = 324

DELTA > 0

x = (324^(1/2)-2)/(1*2) or x = (-324^(1/2)-2)/(1*2)

x = 8 or x = -10

(x+10)*(x-8) = 0

((x+10)*(x-8))/3 = 0

((x+10)*(x-8))/3 = 0 // * 3

(x+10)*(x-8) = 0

( x+10 )

x+10 = 0 // - 10

x = -10

( x-8 )

x-8 = 0 // + 8

x = 8

x in { -10, 8 }

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